1. thực hiện phép tính

a. 75-(3. 5² - 4. 2³)

= 75-(3. 25 - 4. 8)

= 75 - (75- 32)

= 75 - 43

= 32.

b. 18: 3² +5.2³ -27

= 18 : 9 + 5. 8 -27

= 2 + 40 - 27

= 42 - 27

= 15.

c. -12+34 = +(34 - 12) = 22.

d. 50.25+50.75-200

= 50. (25 + 75) - 200

= 50. 100 - 200

= 5000 - 200

= 4800.

e. -35+34+(-25)+16

= [-35 + (-25) ] + (16 + 34 )

= -60 + (16 + 34 )

= -60 + 50

= -10.

f. 27.75+28.75-270

= (27+28) . 75 - 270

= 55. 75 - 270

= 4125 - 270

= 3855.

g. 18.36+18.64-12.55-12.45

= 18 . (36+64) - 12. (55-45)

= 18 . 100 - 12. 10

= 1800 - 120

= 1680.

b: \(=15\left(141+19\right)=15\cdot160=24000\)

c: \(=2^3\cdot\left(17-14\right)=8\cdot3=24\)

a: Ta có: \(\left(8\cdot5^7+5^6-5^5\right):5^5\)

\(=8\cdot5^2+5-1\)

\(=200+4=204\)

b: Ta có: \(\left(9^{30}-27^{19}\right):3^{57}+\left(125^9-25^{12}\right):5^{24}\)

\(=3^{60}:3^{57}-3^{57}:3^{57}+5^{27}:5^{24}-5^{24}:5^{24}\)

\(=27-1+125-1\)

=150

a. (8,5⁷ - 5⁵ + 5⁶) : 5⁵

= (8,5⁷ : 5⁵) - (5⁵ : 5⁵) + (5⁶ : 5⁵)

= 1,7² - 1 + 5

= 2,89 - 1 + 5

= 6,89

b. (9³⁰ - 27¹⁹) : 3⁵⁷ + (125⁹ - 25¹²) : 5²⁴

= (9³⁰ : 3⁵⁷) - (27¹⁹ : 3⁵⁷) + (125⁹ : 5²⁴) - (25¹² : 5²⁴)

= 3³ - 1 + 125 - 1

= 27 - 1 + 125 - 1

= 150

c. (10¹² + 5¹¹ . 2⁹ - 5¹³ - 2⁸) : 4 . 5⁵ . 10⁶

= (10¹² + 2,5 , 10¹⁰ - 5¹³ - 2⁸) : 1,25 . 10¹⁰

= (10¹² : 1,25 . 10¹⁰) + (2,5 . 10¹⁰ : 1,25 . 10¹⁰) - (5¹³ : 1,25 . 10¹⁰) - (2⁸ : 1,25 . 10¹⁰)

= 80 + 2 - \(\dfrac{25}{256}\) - \(\dfrac{1}{48828125}\)

= 81,90234373 \(\approx\) 82

a.

= -30-15+21-30-15-9

= (-30 - 30)+(-15-15)+(21-9)

= -60 -30 + 12

= -78 

b. 

= (6-18)+(-5+4)+(-20+21)

= 12 + (-1) + 1

=12

c. 

= 27.(19+31)

=27. 50 

= 1350 

d. 

= (-25).(64+36)

= -25 . 100

= -2500

e. 18.36 + 72.15

= 18.36 + 4.18.15 

=18.( 36 + 60)

= 18.96

= 1728

a) = 648 + 1152 - 12,55 - 12,45

= 1775

b) = 16 : 2 + 25 . 3 - 29

    = 8 + 75 - 29

    = 54

\(a,\dfrac{-8}{15}+\dfrac{13}{30}-\dfrac{5}{12}=\dfrac{-32}{60}+\dfrac{26}{60}-\dfrac{25}{60}=-\dfrac{31}{60}\\ b,\dfrac{3}{2}.\dfrac{7}{2}+\left(\dfrac{-5}{6}+\dfrac{1}{10}:\dfrac{11}{30}\right)=\dfrac{21}{4}+\left(\dfrac{-5}{6}+\dfrac{3}{11}\right)=\dfrac{21}{4}+\dfrac{-37}{66}=\dfrac{619}{132}\)

\(c,\dfrac{-20}{21}.\dfrac{22}{35}+\dfrac{-20}{21}.\dfrac{13}{35}+\dfrac{-22}{21}=\dfrac{-20}{21}\left(\dfrac{22}{35}+\dfrac{13}{35}\right)+\dfrac{-22}{21}=\dfrac{-20}{21}.1+\dfrac{-22}{21}=\dfrac{-20}{21}+\dfrac{-22}{21}=\dfrac{-42}{21}=-2\)

c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)

\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)

\(=1-2=-1\)

Giải:

a)-1/12+4/3=-1/12+16/12=15/12=5/4

b)(-4/14-3/15)-(1/5-20/35-(-1)).7

=-17/35-22/35.7

=-17/35-22/5

=-171/35

c)3/5+-5/20+30/75+-7/4

=3/5+-1/4+2/5+-7/4

=(3/5+2/5)+(-1/4+-7/4)

=1+-2

=-1

d)5/6.-12/14+7/13

=-5/7+7/13

=-16/91

e)2/-9-5/-36-1/4

=-1/12-1/4

=-1/3

f)2/23+-5/12+7/18+21/23+-7/12

=(2/23+21/23)+(-5/12+-7/12)+7/18

=1+-1+7/18

=7/18